George and Inverse Tangent

[Mads Juul]

Hey some help with George and Pythagoras its been a whil for me...

I have a right angled triangle were I know the length of the two sides a and b(the two others than the longest side the hypotenuse)

so to calculate the angle B

TAN(B) = a/b

so now I have Tangent B

But how do I get B?

-Mads

[Hervé]

B = ATAN( a / b )

[Mads Juul]

ahhh of course . Have forgotten its called ATAN. Thank you Herve
-Mads